Table 1.

Statistical tests summary

FigureData structureType of testNumber of preparationsOutputp value
1CNormalOne-way RM ANOVA, Holm–Sidak post hoc testN = 14F(13,4) = 49.21p < 0.001 (ANOVA)p < 0.05 (post hoc)
1DNormalPaired t testN = 1010 Hz: t(9) = 1.72120 Hz: t(9) = 3.24130 Hz: t(9) = 4.90940 Hz: t(9) = 5.36850 Hz: t(9) = 3.861p = 0.119p = 0.009p < 0.001p < 0.001p < 0.001
3BNormalOne-way RM ANOVAN = 8F(11,4) = 4.17p = 0.06
3DNormalOne-way RM ANOVA, Holm–Sidak post hoc testN = 6F(3,17) = 32.36p < 0.001 (ANOVA)p < 0.01 (post hoc)
4ANormalPaired t testN = 6t(5) = −6.42p = 0.001
4BNormalPaired t testN = 13t(12) = 6.18p = 0.001
4DNormalPaired t testN = 5t(4) = 2.66p = 0.056
4ENormalOne-way RM ANOVA, Holm–Sidak post hoc testN = 5F(4,3) = 33.29p < 0.001 (ANOVA)control saline versus intravenous saline: p < 0.05 (post hoc)control cimet. versus intravenous cimet.: p = 0.58
6CNormalOne-way RM ANOVA, Student–Newman–Keuls post hoc testN = 8F(7,42) = 3.831p = 0.003 (ANOVA)p < 0.05 (post hoc)
6DNormalOne-way RM ANOVA, Student–Newman–Keuls post hoc testN = 8F(7,42) = 9.717p = 0.003 (ANOVA)p < 0.05 (post hoc)
6ENormalOne-way RM ANOVAN = 8F(9,56) = 1.198p = 0.315
7CNormalOne-way RM ANOVA, Student–Newman–Keuls post hoc testN = 5F(4,28) = 4.65p = 0.001 (ANOVA)p < 0.05 (post hoc)
7DNormalOne-way RM ANOVA, Student–Newman–Keuls post hoc testN = 5F(4,28) = 3.29p = 0.038 (ANOVA)p < 0.05 (post hoc)
7ENormalOne-way RM ANOVAN = 5F(4,28) = 1.07p = 0.15
9CNormalPaired t testN = 6, n = 28 APst(27) = −0.89p = 0.38
9ENormalPaired t testN = 8t(7) = 0.7p = 0.5