Table 2.

Statistical differences among the samples illustrated in Figure 4

LocationData referenceData structureType of testPower
aFig. 4B, plot FtNonnormal distributionMann–Whitney U test
eGFP-KCC2 vs. WTU = 185, n = 19,24; p = 0.30
WT vs. ΔNTDU = 161, n = 24,20; p = 0.06
WT vs. ΔCTDU = 357, n = 24,30; p = 0.97
ΔNTD vs. ΔCTDU = 274, n = 20,30; p = 0.72
bFig. 4B, plot FmNonnormal distributionMann–Whitney U test
eGFP-KCC2 vs. WTU = 9, n = 19,24; p = 2.42 × 10–10
WT vs. ΔNTDU = 476, n = 24,20; p = 1.36 × 10–11
WT vs. ΔCTDU = 568, n = 24,30; p = 1.89 × 10–4
ΔNTD vs. ΔCTDU = 26, n = 20,30; p = 4.96 × 10–10
eGFP-KCC2 vs. ΔNTDU = 220, n = 19,20; p = 0.4
eGFP-KCC2 vs. ΔCTDU = 47, n = 19,30; p = 1.09 × 10–6
cFig. 4B, plot FiNonnormal distributionMann–Whitney U test
eGFP-KCC2 vs. WTU = 420, n = 19,24; p = 2.28 × 10–7
WT vs. ΔNTDU = 476, n = 24,20; p = 1.36 × 10–11
WT vs. ΔCTDU = 106, n = 24,30; p = 2.86 × 10–6
ΔNTD vs. ΔCTDU = 8, n = 20,30; p = 2.84 × 10–12
eGFP-KCC2 vs. ΔNTDU = 230, n = 19,20; p = 0.24
eGFP-KCC2 vs. ΔCTDU = 14, n = 19,30; p = 2.58 × 10–8
dFig. 4C, single FmNonnormal distributionMann–Whitney U test
eGFP-KCC2 vs. WTU = 14, n = 19,24; p = 1.27 × 10–9
WT vs. ΔNTDU = 447, n = 24,20; p = 7.95 × 10–12
WT vs. ΔCTDU = 647, n = 24,30; p = 5.59 × 10–8
ΔNTD vs. ΔCTDU = 14, n = 20,30; p = 2.16 × 10–11
eGFP-KCC2 vs. ΔNTDU = 242, n = 19,20; p = 0.15
eGFP-KCC2 vs. ΔCTDU = 70, n = 19,30; p = 1.08 × 10–5
eFig. 4C, Fm densityNonnormal distributionMann–Whitney U test
eGFP-KCC2 vs. WTU = 16, n = 19,24; p = 2.28 × 10–9
WT vs. ΔNTDU = 470, n = 24,20; p = 1.58 × 10–10
WT vs. ΔCTDU = 452, n = 24,30; p = 0.11
ΔNTD vs. ΔCTDU = 33, n = 20,30; p = 2.25 × 10–9
eGFP-KCC2 vs. ΔNTDU = 206, n = 19,20; p = 0.66
eGFP-KCC2 vs. ΔCTDU = 58, n = 19,30; p = 3.36 × 10–6
fFig. 4DNonnormal distributionMann–Whitney U test
eGFP-KCC2 vs. WTU = 0, n = 33,40; p = 2.64 × 10–13
WT vs. ΔNTDU = 1480, n = 40,37; p = 4.69 × 10–14
WT vs. ΔCTDU = 538, n = 40,46; p = 9.56 × 10–4
ΔNTD vs. ΔCTDU = 0, n = 37,46; p = 6.56 × 10–15
eGFP-KCC2 vs. ΔNTDU = 719, n = 33,37; p = 0.2
eGFP-KCC2 vs. ΔCTDU = 0, n = 33,46; p = 4.65 × 10–14